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python計算兩個日期相差多少個月實例代碼

來源:技術員聯盟┆發布時間:2017-09-20 00:58┆點擊:

近期,由于業務需要計算兩個日期之前相差多少個月。我在網上找了很久,結果發現萬能的python,居然沒有一個模塊計算兩個日期的月數,像Java、C#之類的高級語言,都會有(date1-date2).months的現成方法,覺得不可思議。說句實在的,一直覺得python 的日期處理模塊真心不好用。

哦,對了,別跟我說 datetime, calendar, dateutil 這些模塊,因為我都試過了,都沒用。有個竟然算出來還有錯。datetime.timedelta只能計算出日時分秒。對年月卻不支持。網上一搜,一大堆的。

dateutil.rrule這個例子是我好不容易找到的,請看我的測試結果:

import datetime from dateutil import rrule d1 = datetime.date(2016, 2, 29) d2 = datetime.date(2019, 3, 31) months = rrule.rrule(rrule.MONTHLY, dtstart=d1, until=d2).count() print(f"months={months}")

python計算兩個日期相差多少個月實例代碼 三聯

看到這樣的結果,我只能呵呵了。

廢話不多少,獻上自己寫的代碼:

該代碼返回,(月,小數月)

import datetime import calendar as c d1 = datetime.date(2016, 2, 29) d2 = datetime.date(2019, 3, 31) def calmonths(startdate, enddate): # 計算兩個日期相隔月差 samemonthdate = None try: samemonthdate = datetime.date(enddate.year, enddate.month, startdate.day) except Exception as e: print(e) samemonthdate = datetime.date(enddate.year, enddate.month, c.monthrange(enddate.year, enddate.month)[1]) holdmonths = 0 decimalmonth = 0.0 if samemonthdate > enddate: premanthdate = None try: premanthdate = datetime.date(enddate.year, enddate.month - 1, startdate.day) except Exception as e: print(e) premanthdate = datetime.date(enddate.year, enddate.month - 1, c.monthrange( enddate.year, enddate.month - 1)[1]) currmonthdays = (samemonthdate - premanthdate).days holdmonths = (premanthdate.year - startdate.year ) * 12 + premanthdate.month - startdate.month decimalmonth = (enddate - premanthdate).days / currmonthdays elif samemonthdate < enddate: nextmonthdate = None try: nextmonthdate = datetime.date(enddate.year, enddate.month + 1, startdate.day) except Exception as e: nextmonthdate = datetime.date(enddate.year, enddate.month + 1, c.monthrange( enddate.year, enddate.month + 1)[1]) currmonthdays = (nextmonthdate - samemonthdate).days holdmonths = (samemonthdate.year - startdate.year ) * 12 + samemonthdate.month - startdate.month decimalmonth = (enddate - samemonthdate).days / currmonthdays else: holdmonths = (enddate.year - startdate.year ) * 12 + enddate.month - startdate.month return holdmonths, decimalmonth months = calmonths(d1, d2) print(f"months={months}")

python計算兩個日期相差多少個月實例代碼